UPSC Prelims 2005 · General Studies
Question 144: International Relations and Current Affairs
Match items in List-I with List-II and select the correct answer using the codes given below the lists: List-I (Lawn Tennis Tournament) A. French Open 2004 B. Wimbledon 2004 C. US Open 2004 D. Australian Open 2004 List-II (Winner of Women’s Singles) 1. Svetlana Kuznetsova 2. Anastasia Myskina 3. Maria Sharapova 4. Serena Williams 5. Justine Henin Harden
AnswerThe answer is (b).
In 2004 the women's singles champions were Anastasia Myskina (French Open), Maria Sharapova (Wimbledon), Svetlana Kuznetsova (US Open) and Justine Henin-Hardenne (Australian Open). That gives A-2, B-3, C-1, D-5. Serena Williams won Wimbledon in 2002 and 2003 and the Australian Open in 2003, not in 2004.
- A. French Open 2004 - Anastasia Myskina (2).
- B. Wimbledon 2004 - Maria Sharapova (3).
- C. US Open 2004 - Svetlana Kuznetsova (1).
- D. Australian Open 2004 - Justine Henin-Hardenne (5).
Why each option is right or wrong
- (a) Gives the French Open to Henin; Myskina won it.
- (b) Correct: Myskina, Sharapova, Kuznetsova, Henin.
- (c) Gives the French Open to Henin; Myskina won it.
- (d) Gives Wimbledon to Kuznetsova; Sharapova won it.
Explanation: written by UPSC Grade, not by UPSC.
Source: UPSC, Civil Services (Preliminary) Examination 2005, General Studies. UPSC's own paper isn't online; the words are from a published compilation. The paper on upsc.gov.in.