2026 CSAT, all questions

UPSC Prelims 2026 · CSAT

Question 49: Basic Numeracy

How many times does 5 appear in all two-digit positive integers?

a18
b19
c20
d21

AnswerUPSC’s answer is (b).

Count the digit 5 by place. In the units place, 15, 25, ..., 95 give 9 numbers. In the tens place, 50 to 59 give 10 numbers. The number 55 has two 5s, one counted in each group, so the digit appears 9 + 10 = 19 times.

How you could have got this

No shortcut here: in a “how many” question, ruling out options doesn’t help. Every statement has to be judged.

This follows UPSC’s provisional key; the final key could change it.

Which options go is worked out from UPSC’s key and the options, not by a model.

Why each option is right or wrong
  • (a) Wrong: 18 drops one occurrence, usually the second 5 in 55.
  • (b) Right: 9 + 10 = 19.
  • (c) Wrong: 20 overcounts; the single digit 5 is not a two-digit number.
  • (d) Wrong: 21 overcounts.

Only the provisional key (27 May 2026) was found; the final key replaces it when found.

Answer: UPSC’s key. Explanation: written by UPSC Grade, not by UPSC.

Source: UPSC, Civil Services (Preliminary) Examination 2026, General Studies Paper II (CSAT), Series A. The paper on upsc.gov.in.