2018 CSAT, all questions

UPSC Prelims 2018 · CSAT

Question 69: Basic Numeracy

A person bought a refrigerator worth ₹22,800 with 12·5% interest compounded yearly. At the end of first year he paid ₹8,650 and at the end of second year ₹9,125. How much will he have to pay at the end of third year to clear the debt?

a₹9,990
b₹10,000
c₹10,590
d₹11,250

AnswerUPSC’s answer is (d).

Add 12.5% each year, then subtract the payment. Year 1: 22,800 × 1.125 = 25,650; less 8,650 leaves 17,000. Year 2: 17,000 × 1.125 = 19,125; less 9,125 leaves 10,000. Year 3: 10,000 × 1.125 = 11,250, which clears the debt. Interest must be added to the balance before each payment.

Why each option is right or wrong
  • (a) 9,990 would not clear the debt, which stands at 11,250 with interest.
  • (b) 10,000 is the balance after year two, before the third year's interest.
  • (c) 10,590 does not match 10,000 × 1.125.
  • (d) Correct: 10,000 × 1.125 = 11,250.

Answer: UPSC’s key. Explanation: written by UPSC Grade, not by UPSC.

Source: UPSC, Civil Services (Preliminary) Examination 2018, General Studies Paper II (CSAT), Series A. The paper on upsc.gov.in.