2014 CSAT, all questions

UPSC Prelims 2014 · CSAT

Question 65: Basic Numeracy

Four persons, Alok, Bhupesh, Chander and Dinesh have a total of ₹ 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact ₹ 5 more than Dinesh has. Who has the maximum amount of money ?

aAlok
bBhupesh
cChander
dDinesh

AnswerUPSC’s answer is (a).

The total is 100. Alok + Bhupesh = Chander + Dinesh, so each pair has 50. Chander has half of Dinesh's money, so Dinesh has two thirds of 50, about 33.33, and Chander about 16.67. Alok has 5 more than Dinesh, about 38.33, so Bhupesh has 50 - 38.33, about 11.67. The largest amount is Alok's.

Why each option is right or wrong
  • (a) Right. Alok has about 38.33, the most.
  • (b) Bhupesh has the least, about 11.67.
  • (c) Chander has about 16.67.
  • (d) Dinesh has about 33.33, less than Alok.

Answer: UPSC’s key. Explanation: written by UPSC Grade, not by UPSC.

Source: UPSC, Civil Services (Preliminary) Examination 2014, General Studies Paper II (CSAT), Series A. The paper on upsc.gov.in.